Consider the parabola y=x^2 the shaded area is 304899

 72 Finding Volume Using Cross Sections Warm Up Find the area of the following figures 1 A square with sides of length x 2 A square with diagonals of length x 3 A semicircle of radius x 4 A semicircle of diameter x 5 An equilateral triangle with sides of length x 6 An isosceles right triangle with legs of length x

Consider the parabola y=x^2 the shaded area is-The focus of a parabola can be found by adding to the ycoordinate if the parabola opens up or down Substitute the known values of , , and into the formula and simplify Find the axis of symmetry by finding the line that passes through the vertex and the focus19 Consider The Parabola Y 1 1 The Shaded Area Is Win Wi Lessons 5 Graph y=2xx^2 Find the properties of the given parabola Tap for more Reorder and Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the Graph the parabola using its

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Consider The Parabola Y X 2 The Shaded Area Is
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Consider The Parabola Y X 2 The Shaded Area Is
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Y 2 /2 ≤ x ≤ y 4} Solution Consider equations from the given inequalities, y 2 = 2x and x – y = 4 Here, y 2 = 2x is equation of parabola open towards the ve xaxis and having focus (1/2, 0) and x – y = 4, is a straight line Solving above equations, we get y 2 = 2(y 4) or y Best answer Given Two curves are y2 = 4x and y = 2x – 4 Now to find the area between these two curves, we have to find common area ie Shaded portion Intersection of parabola y2 = 4x with line y = 2x – 4 Putting the value of y from the equation of a line in parabola equation, we get, y2 = 4x ⇒ (2x – 4)2 = 4x

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